0.004 M Sodium lauryl sulfate
[NOTESulfuric acid is included in this solution to inhibit precipitate formation. If a precipitate forms under storage, discard the solution, and prepare and standardize a fresh
0.004 M Sodium lauryl sulfate solution.
] Dissolve 1.15 g of sodium lauryl sulfate in 500 mL of water, add 2 mL of sulfuric acid, dilute with water to 1000 mL, and mix. Determine the molarity of the solution as follows. Transfer to a glass-stoppered, 100-mL cylinder 10.0 mL of 0.004
M cetylpyridinium chloride (1.432 mg of
USP Cetylpyridinium Chloride RS per mL in water), add 5 mL of 2 N sulfuric acid, 20 mL of chloroform, and 1 mL of
methyl yellow TS, and titrate with the sodium lauryl sulfate solution, with frequent vigorous shaking, until the chloroform layer acquires the first permanent orange-pink color. Calculate the molarity, and restandardize before each use.
Procedure
Dissolve an accurately determined number (about 100) of Cetylpyridinium Chloride Lozenges in about 400 mL of water in a 500-mL volumetric flask, dilute with water to volume, and mix. Transfer an accurately measured aliquot of this solution, equivalent to about 10 mg of cetylpyridinium chloride, to a glass-stoppered, 100-mL cylinder, and add 5 mL of 2 N sulfuric acid, 20 mL of chloroform, and 1 mL of
methyl yellow TS. Insert the stopper, shake until the chloroform layer develops a bright yellow color, and titrate with
0.004 M Sodium lauryl sulfate, shaking thoroughly after each addition, until the chloroform layer develops the first permanent orange-pink color. Each mL of
0.004 M Sodium lauryl sulfate is equivalent to 1.432 mg of C
21H
38ClN·H
2O.