Packaging and storage
Preserve in tight containers, and store at controlled room temperature.
Chloride 221
A 1.0-g portion shows no more chloride than corresponds to 0.70 mL of 0.020 N hydrochloric acid (0.05%).
Sulfate 221
A 1.0-g portion shows no more sulfate than corresponds to 0.30 mL of 0.020 N sulfuric acid (0.03%).
Chromatographic purity
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Dissolve an accurately weighed quantity of Alanine in water to obtain a solution having a concentration of 10 mg per mL. Apply 5 µL.
Standard solution
Dissolve an accurately weighed quantity of USP L-Alanine RS in water to obtain a solution having a known concentration of about 0.05 mg per mL. Apply 5 µL. [NOTEThis solution has a concentration equivalent to about 0.5% of that of the Test solution.]
System suitability solution
Prepare a solution in water containing 0.4 mg each of USP
L-Alanine RS and
USP Glycine RS per mL. Apply 5 µL.
Spray reagent
Dissolve 0.2 g of ninhydrin in 100 mL of a mixture of butyl alcohol and 2 N acetic acid (95:5).
Developing solvent system
Prepare a mixture of butyl alcohol, glacial acetic acid, and water (60:20:20).
Procedure
Proceed as directed for
Thin-Layer Chromatography under
Chromatography 621. After air-drying the plate, repeat the development process. After air-drying a second time, spray with
Spray reagent, and heat between 100
and 105
for about 15 minutes. Examine the plate under white light. The chromatogram obtained from the
System suitability solution exhibits two clearly separated spots. Any secondary spot in the chromatogram obtained from the
Test solution is not larger or more intense than the principal spot in the chromatogram obtained from the
Standard solution: not more than 0.5% of any individual impurity is found, and not more than 2.0% of total impurities is found.
Assay
Transfer about 80 mg of Alanine, accurately weighed, to a 125-mL flask, dissolve in a mixture of 3 mL of formic acid and 50 mL of glacial acetic acid, and titrate with 0.1 N perchloric acid VS, determining the endpoint potentiometrically. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N perchloric acid is equivalent to 8.909 mg of C3H7NO2.
Auxiliary Information
Staff Liaison :
Lawrence Evans, III, Ph.D., Scientist
Expert Committee : (DSN05) Dietary Supplements - Non-Botanicals
USP29NF24 Page 60
Pharmacopeial Forum : Volume No. 27(5) Page 2973
Phone Number : 1-301-816-8389